What is 0.5y^2=-0.5x^2+12.5 ?

The solution to 0.5y^2=-0.5x^2+12.5 is Circle with (a,b)=(0,0),r=5

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0.5y^2=-0.5x^2+12.5

0.5 y^{2} = - 0.5 x^{2} + 12.5

(a, b) = (0, 0), r = 5

Solution steps

0.5 y^{2} = - 0.5 x^{2} + 12.5

Rewrite

0.5 y^{2} = - 0.5 x^{2} + 12.5

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

p^{2} + q^{2} = 1

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

(x - 5)^{2} + (y + 7)^{2} = 4

What is 0.5y^2=-0.5x^2+12.5 ?
The solution to 0.5y^2=-0.5x^2+12.5 is Circle with (a,b)=(0,0),r=5