What is x^2+y^2+14x-6y-6=0 ?

The solution to x^2+y^2+14x-6y-6=0 is Circle with (a,b)=(-7,3),r=8

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x^2+y^2+14x-6y-6=0

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

(a, b) = (- 7, 3), r = 8

Solution steps

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

Rewrite

x^{2} + y^{2} + 14 x - 6 y - 6 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 3)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 7, 3), r = 8

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

(x - 5)^{2} + (y + 7)^{2} = 4

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

x^{2} + y^{2} = 2 3^{2}

What is x^2+y^2+14x-6y-6=0 ?
The solution to x^2+y^2+14x-6y-6=0 is Circle with (a,b)=(-7,3),r=8