What is x^2+y^2+6x+2y-15=0 ?

The solution to x^2+y^2+6x+2y-15=0 is Circle with (a,b)=(-3,-1),r=5

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x^2+y^2+6x+2y-15=0

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

(a, b) = (- 3, - 1), r = 5

Solution steps

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

Rewrite

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 1))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 1), r = 5

x^{2} + y^{2} + 12 \cdot (- 4) y + 4 = 0

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

x^{2} + y^{2} - 10 x - 2 y - 74 = 0

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

What is x^2+y^2+6x+2y-15=0 ?
The solution to x^2+y^2+6x+2y-15=0 is Circle with (a,b)=(-3,-1),r=5