What is (x-6)^2+(y-10)^2=5^2 ?

The solution to (x-6)^2+(y-10)^2=5^2 is Circle with (a,b)=(6,10),r=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-6)^2+(y-10)^2=5^2

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

(a, b) = (6, 10), r = 5

Solution steps

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

Rewrite

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

in the form of the standard circle equation

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (6, 10), r = 5

x^{2} + y^{2} - 4 x + 2 y - 76 = 0

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

x^{2} + y^{2} + 12 \cdot (- 4) y + 4 = 0

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

What is (x-6)^2+(y-10)^2=5^2 ?
The solution to (x-6)^2+(y-10)^2=5^2 is Circle with (a,b)=(6,10),r=5