What is x^2+y^2+12*(-4)y+4=0 ?

The solution to x^2+y^2+12*(-4)y+4=0 is Circle with (a,b)=(0,24),r=2sqrt(143)

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x^2+y^2+12*(-4)y+4=0

x^{2} + y^{2} + 12 \cdot (- 4) y + 4 = 0

(a, b) = (0, 24), r = 2143

Solution steps

x^{2} + y^{2} + 12 (- 4) y + 4 = 0

Rewrite

x^{2} + y^{2} + 12 \cdot (- 4) y + 4 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 24)^{2} = (2143)^{2}

Therefore the circle properties are:

(a, b) = (0, 24), r = 2143

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9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

4 x^{2} + 4 y^{2} - 32 y + 39 = 0

What is x^2+y^2+12*(-4)y+4=0 ?
The solution to x^2+y^2+12*(-4)y+4=0 is Circle with (a,b)=(0,24),r=2sqrt(143)