What is x^2+y^2-20x-14y+100=0 ?

The solution to x^2+y^2-20x-14y+100=0 is Circle with (a,b)=(10,7),r=7

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x^2+y^2-20x-14y+100=0

x^{2} + y^{2} - 20 x - 14 y + 100 = 0

(a, b) = (10, 7), r = 7

Solution steps

x^{2} + y^{2} - 20 x - 14 y + 100 = 0

Rewrite

x^{2} + y^{2} - 20 x - 14 y + 100 = 0

in the form of the standard circle equation

(x - 10)^{2} + (y - 7)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (10, 7), r = 7

(x - 4)^{2} + (Y (x) + 2)^{2} = 4

x^{2} + y^{2} - 4 x + 8 y = - 4

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} + 112. 6^{2} = 180. 3^{2}

x^{2} + y^{2} = 5200

y^{2} + x^{2} = 160

What is x^2+y^2-20x-14y+100=0 ?
The solution to x^2+y^2-20x-14y+100=0 is Circle with (a,b)=(10,7),r=7