What is (x-4)^2+(Y(x)+2)^2=4 ?

The solution to (x-4)^2+(Y(x)+2)^2=4 is Circle with (a,b)=(4,-2),r=2

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(x-4)^2+(Y(x)+2)^2=4

(x - 4)^{2} + (Y (x) + 2)^{2} = 4

(a, b) = (4, - 2), r = 2

Solution steps

(x - 4)^{2} + (y + 2)^{2} = 4

Rewrite

(x - 4)^{2} + (y + 2)^{2} = 4

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 2))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (4, - 2), r = 2

x^{2} + y^{2} - 4 x + 8 y = - 4

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} + 112. 6^{2} = 180. 3^{2}

x^{2} + y^{2} = 5200

y^{2} + x^{2} = 160

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

What is (x-4)^2+(Y(x)+2)^2=4 ?
The solution to (x-4)^2+(Y(x)+2)^2=4 is Circle with (a,b)=(4,-2),r=2