What is (x*1)^2+(y-1)^2=5 ?

The solution to (x*1)^2+(y-1)^2=5 is Circle with (a,b)=(0,1),r=sqrt(5)

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(x*1)^2+(y-1)^2=5

(x \cdot 1)^{2} + (y - 1)^{2} = 5

(a, b) = (0, 1), r = 5

Solution steps

(x \cdot 1)^{2} + (y - 1)^{2} = 5

Rewrite

(x \cdot 1)^{2} + (y - 1)^{2} = 5

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 5

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

a^{2} + b^{2} = a + 2

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

a^{2} + b^{2} + 0.02 = 1

What is (x*1)^2+(y-1)^2=5 ?
The solution to (x*1)^2+(y-1)^2=5 is Circle with (a,b)=(0,1),r=sqrt(5)