What is (x-7)^2+(y+4)^2=25 ?

The solution to (x-7)^2+(y+4)^2=25 is Circle with (a,b)=(7,-4),r=5

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(x-7)^2+(y+4)^2=25

(x - 7)^{2} + (y + 4)^{2} = 25

(a, b) = (7, - 4), r = 5

Solution steps

(x - 7)^{2} + (y + 4)^{2} = 25

Rewrite

(x - 7)^{2} + (y + 4)^{2} = 25

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (7, - 4), r = 5

(x - 9)^{2} + y^{2} = 10

x^{(2)} + y^{(2)} + 4 x + 6 y - 23 = 0

y^{2} + x^{2} - 12 x = 0

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

x^{2} + y^{2} - \frac{27}{8} x + \frac{31}{8} y - \frac{39}{8} = 0

What is (x-7)^2+(y+4)^2=25 ?
The solution to (x-7)^2+(y+4)^2=25 is Circle with (a,b)=(7,-4),r=5