What is (y-10)^2+(x-10)^2=5^2 ?

The solution to (y-10)^2+(x-10)^2=5^2 is Circle with (a,b)=(10,10),r=5

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(y-10)^2+(x-10)^2=5^2

(y - 10)^{2} + (x - 10)^{2} = 5^{2}

(a, b) = (10, 10), r = 5

Solution steps

(y - 10)^{2} + (x - 10)^{2} = 5^{2}

Rewrite

(y - 10)^{2} + (x - 10)^{2} = 5^{2}

in the form of the standard circle equation

(x - 10)^{2} + (y - 10)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (10, 10), r = 5

(x - 7)^{2} + (y + 4)^{2} = 25

(x - 9)^{2} + y^{2} = 10

x^{(2)} + y^{(2)} + 4 x + 6 y - 23 = 0

y^{2} + x^{2} - 12 x = 0

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

What is (y-10)^2+(x-10)^2=5^2 ?
The solution to (y-10)^2+(x-10)^2=5^2 is Circle with (a,b)=(10,10),r=5