What is (x-9)^2+y^2=10 ?

The solution to (x-9)^2+y^2=10 is Circle with (a,b)=(9,0),r=sqrt(10)

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(x-9)^2+y^2=10

(x - 9)^{2} + y^{2} = 10

(a, b) = (9, 0), r = 10

Solution steps

(x - 9)^{2} + y^{2} = 10

Rewrite

(x - 9)^{2} + y^{2} = 10

in the form of the standard circle equation

(x - 9)^{2} + (y - 0)^{2} = (10)^{2}

Therefore the circle properties are:

(a, b) = (9, 0), r = 10

x^{(2)} + y^{(2)} + 4 x + 6 y - 23 = 0

y^{2} + x^{2} - 12 x = 0

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

x^{2} + y^{2} - \frac{27}{8} x + \frac{31}{8} y - \frac{39}{8} = 0

x^{2} + y^{2} + 8 x - 12 y = 0

What is (x-9)^2+y^2=10 ?
The solution to (x-9)^2+y^2=10 is Circle with (a,b)=(9,0),r=sqrt(10)