What is y^2+x^2-12x=0 ?

The solution to y^2+x^2-12x=0 is Circle with (a,b)=(6,0),r=6

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y^2+x^2-12x=0

y^{2} + x^{2} - 12 x = 0

(a, b) = (6, 0), r = 6

Solution steps

y^{2} + x^{2} - 12 x = 0

Rewrite

y^{2} + x^{2} - 12 x = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (6, 0), r = 6

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

x^{2} + y^{2} - \frac{27}{8} x + \frac{31}{8} y - \frac{39}{8} = 0

x^{2} + y^{2} + 8 x - 12 y = 0

x^{2} + y^{2} \leq 12

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

What is y^2+x^2-12x=0 ?
The solution to y^2+x^2-12x=0 is Circle with (a,b)=(6,0),r=6