What is (x-2)^2+(y-3)^2=8 ?

The solution to (x-2)^2+(y-3)^2=8 is Circle with (a,b)=(2,3),r=sqrt(8)

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(x-2)^2+(y-3)^2=8

(x - 2)^{2} + (y - 3)^{2} = 8

(a, b) = (2, 3), r = 8

Solution steps

(x - 2)^{2} + (y - 3)^{2} = 8

Rewrite

(x - 2)^{2} + (y - 3)^{2} = 8

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = (8)^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 8

(x - 4)^{2} + (y - 4)^{2} = 4

(x - 4)^{2} + (y - 4)^{2} = 6

(x - (- 4))^{2} + (y - 5)^{2} = 42

x^{2} + y^{2} - 5 x - 6 = 0

(x + 6)^{2} + y^{2} = 8

What is (x-2)^2+(y-3)^2=8 ?
The solution to (x-2)^2+(y-3)^2=8 is Circle with (a,b)=(2,3),r=sqrt(8)