What is (x-(-4))^2+(y-5)^2=sqrt(42) ?

The solution to (x-(-4))^2+(y-5)^2=sqrt(42) is Circle with (a,b)=(-4,5),r=sqrt(\sqrt{42)}

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(x-(-4))^2+(y-5)^2=sqrt(42)

(x - (- 4))^{2} + (y - 5)^{2} = 42

(a, b) = (- 4, 5), r = 42

Solution steps

(x - (- 4))^{2} + (y - 5)^{2} = 42

Rewrite

(x - (- 4))^{2} + (y - 5)^{2} = 42

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 5)^{2} = (42)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 5), r = 42

x^{2} + y^{2} - 5 x - 6 = 0

(x + 6)^{2} + y^{2} = 8

(x + 5)^{2} + (y + 1)^{2} = 36

(x + 7)^{2} + (y - 1)^{2} = 225

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

What is (x-(-4))^2+(y-5)^2=sqrt(42) ?
The solution to (x-(-4))^2+(y-5)^2=sqrt(42) is Circle with (a,b)=(-4,5),r=sqrt(\sqrt{42)}