What is (x-4)^2+(y-4)^2=4 ?

The solution to (x-4)^2+(y-4)^2=4 is Circle with (a,b)=(4,4),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-4)^2+(y-4)^2=4

(x - 4)^{2} + (y - 4)^{2} = 4

(a, b) = (4, 4), r = 2

Solution steps

(x - 4)^{2} + (y - 4)^{2} = 4

Rewrite

(x - 4)^{2} + (y - 4)^{2} = 4

in the form of the standard circle equation

(x - 4)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (4, 4), r = 2

(x - 4)^{2} + (y - 4)^{2} = 6

(x - (- 4))^{2} + (y - 5)^{2} = 42

x^{2} + y^{2} - 5 x - 6 = 0

(x + 6)^{2} + y^{2} = 8

(x + 5)^{2} + (y + 1)^{2} = 36

What is (x-4)^2+(y-4)^2=4 ?
The solution to (x-4)^2+(y-4)^2=4 is Circle with (a,b)=(4,4),r=2