What is x^2+y^2+2x+2y+8-36=0 ?

The solution to x^2+y^2+2x+2y+8-36=0 is Circle with (a,b)=(-1,-1),r=sqrt(30)

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x^2+y^2+2x+2y+8-36=0

x^{2} + y^{2} + 2 x + 2 y + 8 - 36 = 0

(a, b) = (- 1, - 1), r = 30

Solution steps

x^{2} + y^{2} + 2 x + 2 y + 8 - 36 = 0

Rewrite

x^{2} + y^{2} + 2 x + 2 y + 8 - 36 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = (30)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 30

x^{2} + y^{2} + 4 x - 6 y - 36 = 0

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 1

x^{2} + y^{2} - 34 = 3 x

x^{2} + y^{2} + 10 x - 10 y + 41 = 0

5 x^{2} + x + 5 y^{2} - y - 9 = 0

What is x^2+y^2+2x+2y+8-36=0 ?
The solution to x^2+y^2+2x+2y+8-36=0 is Circle with (a,b)=(-1,-1),r=sqrt(30)