What is x^2+y^2-9x-2y+17=0 ?

The solution to x^2+y^2-9x-2y+17=0 is Circle with (a,b)=(9/2 ,1),r=(sqrt(17))/2

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x^2+y^2-9x-2y+17=0

x^{2} + y^{2} - 9 x - 2 y + 17 = 0

(a, b) = (\frac{9}{2}, 1), r = \frac{17}{2}

Solution steps

x^{2} + y^{2} - 9 x - 2 y + 17 = 0

Rewrite

x^{2} + y^{2} - 9 x - 2 y + 17 = 0

in the form of the standard circle equation

(x - \frac{9}{2})^{2} + (y - 1)^{2} = (\frac{17}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{9}{2}, 1), r = \frac{17}{2}

x^{2} + y^{2} - 12 x + 8 y + 47 = 0

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

x^{2} - 6 x + y^{2} - 4 y = - 9

(x - 10)^{2} + (y - 5)^{2} = 28

f (x) (f (x)) = - x^{2} + 3 x

What is x^2+y^2-9x-2y+17=0 ?
The solution to x^2+y^2-9x-2y+17=0 is Circle with (a,b)=(9/2 ,1),r=(sqrt(17))/2