What is x^2+y^2+10x-20=0 ?

The solution to x^2+y^2+10x-20=0 is Circle with (a,b)=(-5,0),r=3sqrt(5)

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x^2+y^2+10x-20=0

x^{2} + y^{2} + 10 x - 20 = 0

(a, b) = (- 5, 0), r = 35

Solution steps

x^{2} + y^{2} + 10 x - 20 = 0

Rewrite

x^{2} + y^{2} + 10 x - 20 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 0)^{2} = (35)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 0), r = 35

x^{2} + y^{2} + 2 - 3 x + 2 y - 5 = 0

x^{2} + y^{2} - 10 x - 8 y + 5 = 0

x^{2} + y^{2} = 520

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

4 x^{2} - 4 + 4 y^{2} + 4 y = 9

What is x^2+y^2+10x-20=0 ?
The solution to x^2+y^2+10x-20=0 is Circle with (a,b)=(-5,0),r=3sqrt(5)