What is the circumference (x-2)^2+(y+3)^2=sqrt(11)^2 ?

The circumference (x-2)^2+(y+3)^2=sqrt(11)^2 is C=2sqrt(11)pi

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circumference (x-2)^2+(y+3)^2=sqrt(11)^2

circumference

(x - 2)^{2} + (y + 3)^{2} = 11^{2}

C = 211 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 2)^{2} + (y + 3)^{2} = 11^{2} : r = (11)^{2}

C = 2 π (11)^{2}

Refine

C = 211 π

x^{2} + y^{2} - 10 x + 6 y = 0

4 x^{2} + 4 y^{2} - 8 x + 24 y = 24

x^{2} + y^{2} + 4 x - 10 y + 13 = 0

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

x^{2} + y^{2} - 10 x - 6 y + 9 = 0

What is the circumference (x-2)^2+(y+3)^2=sqrt(11)^2 ?
The circumference (x-2)^2+(y+3)^2=sqrt(11)^2 is C=2sqrt(11)pi