What is the foci ((x+5)^2)/(100)+((y-4)^2)/(64)=1 ?

The foci ((x+5)^2)/(100)+((y-4)^2)/(64)=1 is (1,4),(-11,4)

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foci ((x+5)^2)/(100)+((y-4)^2)/(64)=1

foci

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{64} = 1

(1, 4), (- 11, 4)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 4 ) ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (- 5, 4), a = 10, b = 8

(- 5 + c, 4), (- 5 - c, 4)

Compute

c :

c = 1 0^{2} - 8^{2} : 6

(- 5 + 6, 4), (- 5 - 6, 4)

Refine

(1, 4), (- 11, 4)

9 x^{2} + 16 y^{2} - 72 x + 64 y - 368 = 0

7 x^{2} + 2 y^{2} = 14

25 x^{2} + 36 y^{2} = 900

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 4 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{5} = 1

What is the foci ((x+5)^2)/(100)+((y-4)^2)/(64)=1 ?
The foci ((x+5)^2)/(100)+((y-4)^2)/(64)=1 is (1,4),(-11,4)