What is the foci (x^2)/(100)+(y^2)/(50)=1 ?

The foci (x^2)/(100)+(y^2)/(50)=1 is (5sqrt(2),0),(-5sqrt(2),0)

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foci (x^2)/(100)+(y^2)/(50)=1

foci

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1

(52, 0), (- 52, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{50} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 52

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 0^{2} - (52)^{2} : 52

(0 + 52, 0), (0 - 52, 0)

Refine

(52, 0), (- 52, 0)

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

9 x^{2} + 16 y^{2} + 64 y - 80 = 0

4 x^{2} + y^{2} = 4 x

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

What is the foci (x^2)/(100)+(y^2)/(50)=1 ?
The foci (x^2)/(100)+(y^2)/(50)=1 is (5sqrt(2),0),(-5sqrt(2),0)