What is the foci (x^2)/(49)+(y^2)/(81)=1 ?

The foci (x^2)/(49)+(y^2)/(81)=1 is (0,4sqrt(2)),(0,-4sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/(49)+(y^2)/(81)=1

foci

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1

(0, 42), (0, - 42)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{49} + \frac{y ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 7

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 7^{2} : 42

(0, 0 + 42), (0, 0 - 42)

Refine

(0, 42), (0, - 42)

25 x^{2} + 16 y^{2} + 100 x + 96 y - 156 = 0

9 x^{2} + 16 y^{2} + 64 y - 80 = 0

4 x^{2} + y^{2} = 4 x

9 x^{2} + 9 y^{2} + 18 x - 18 y + 14 = 0

\frac{x ^{2}}{81} + \frac{y ^{2}}{64} = 1

What is the foci (x^2)/(49)+(y^2)/(81)=1 ?
The foci (x^2)/(49)+(y^2)/(81)=1 is (0,4sqrt(2)),(0,-4sqrt(2))