What is the foci (x^2)/(81)+(y^2)/(25)=1 ?

The foci (x^2)/(81)+(y^2)/(25)=1 is (2sqrt(14),0),(-2sqrt(14),0)

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foci (x^2)/(81)+(y^2)/(25)=1

foci

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1

(214, 0), (- 214, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 9, b = 5

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 9^{2} - 5^{2} : 214

(0 + 214, 0), (0 - 214, 0)

Refine

(214, 0), (- 214, 0)

81 x^{2} + 64 y^{2} = 5184

x^{2} + 2 y^{2} - 8 y + 4 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1

\frac{x ^{2}}{16} + y^{2} = 1

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

What is the foci (x^2)/(81)+(y^2)/(25)=1 ?
The foci (x^2)/(81)+(y^2)/(25)=1 is (2sqrt(14),0),(-2sqrt(14),0)