What is the foci+(x^2}{16}+\frac{y^2)/4 =1 ?

The foci+(x^2}{16}+\frac{y^2)/4 =1 is (2sqrt(3),0),(-2sqrt(3),0)

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foci+(x^2}{16}+\frac{y^2)/4 =1

foci

+ \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1

(23, 0), (- 23, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

+ \frac{x ^{2}}{16} + \frac{y ^{2}}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 4^{2} - 2^{2} : 23

(0 + 23, 0), (0 - 23, 0)

Refine

(23, 0), (- 23, 0)

\frac{x ^{2}}{81} + \frac{y ^{2}}{25} = 1

81 x^{2} + 64 y^{2} = 5184

x^{2} + 2 y^{2} - 8 y + 4 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{64} = 1

\frac{x ^{2}}{16} + y^{2} = 1

What is the foci+(x^2}{16}+\frac{y^2)/4 =1 ?
The foci+(x^2}{16}+\frac{y^2)/4 =1 is (2sqrt(3),0),(-2sqrt(3),0)