What is (-x^2)/5+(y^2)/7 =1 ?

The solution to (-x^2)/5+(y^2)/7 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(5),b=sqrt(7)

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(-x^2)/5+(y^2)/7 =1

\frac{- x ^{2}}{5} + \frac{y ^{2}}{7} = 1

(h, k) = (0, 0), a = 5, b = 7

Solution steps

\frac{- x ^{2}}{5} + \frac{y ^{2}}{7} = 1

Rewrite

\frac{- x ^{2}}{5} + \frac{y ^{2}}{7} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{( 5 ) ^{2}} - \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 7

\frac{( x + 2 ) ^{2}}{4} - (y + 4)^{2} = 1

(x - 2 y) (x + 2 y) = 4

16 x^{2} - 3 y^{2} - 32 x + 12 y - 44 = 0

\frac{( y + 1 ) ^{2}}{36} - \frac{( x - 4 ) ^{2}}{4} = 1

\frac{y ^{2}}{100} - \frac{x ^{2}}{64} = 1

What is (-x^2)/5+(y^2)/7 =1 ?
The solution to (-x^2)/5+(y^2)/7 =1 is Hyperbola with (h,k)=(0,0),a=sqrt(5),b=sqrt(7)