What is 4y^2-x^2+16y+12=0 ?

The solution to 4y^2-x^2+16y+12=0 is Hyperbola with (h,k)=(0,-2),a=1,b=2

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4y^2-x^2+16y+12=0

4 y^{2} - x^{2} + 16 y + 12 = 0

(h, k) = (0, - 2), a = 1, b = 2

Solution steps

4 y^{2} - x^{2} + 16 y + 12 = 0

Rewrite

4 y^{2} - x^{2} + 16 y + 12 = 0

in the form of a standard hyperbola equation

\frac{( y - ( - 2 ) ) ^{2}}{1 ^{2}} - \frac{( x - 0 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, - 2), a = 1, b = 2

3 x^{2} - 3 y^{2} + x + y + 1 = 0

- 4 x^{2} + y^{2} - 40 x - 16 = 0

x^{2} + 8 x - y^{2} - 4 y = 5

- 9 y^{2} + 9 z^{2} = 4

\frac{y ^{2}}{6} - \frac{x ^{2}}{3} = 1

What is 4y^2-x^2+16y+12=0 ?
The solution to 4y^2-x^2+16y+12=0 is Hyperbola with (h,k)=(0,-2),a=1,b=2