What is (50)/(x+y)+8/(x-y)=7 ?

The solution to (50)/(x+y)+8/(x-y)=7 is Hyperbola with (h,k)=(29/7 ,3),a= 20/7 ,b= 20/7

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(50)/(x+y)+8/(x-y)=7

\frac{50}{x + y} + \frac{8}{x - y} = 7

(h, k) = (\frac{29}{7}, 3), a = \frac{20}{7}, b = \frac{20}{7}

Solution steps

\frac{50}{x + y} + \frac{8}{x - y} = 7

Rewrite

\frac{50}{x + y} + \frac{8}{x - y} = 7

in the form of a standard hyperbola equation

\frac{( x - \frac{29}{7} ) ^{2}}{( \frac{20}{7} ) ^{2}} - \frac{( y - 3 ) ^{2}}{( \frac{20}{7} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (\frac{29}{7}, 3), a = \frac{20}{7}, b = \frac{20}{7}

4 x^{2} - 9 y^{2} - 16 x + 36 y = 56

x, \frac{x ^{2}}{4} + 1 = 3 m (x)^{2} - 1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

(\frac{( x + 1 )}{16})^{2} - (\frac{( y - 4 )}{25})^{2} = 1

x^{2} - 4 y^{2} - 4 x - 12 = 0

What is (50)/(x+y)+8/(x-y)=7 ?
The solution to (50)/(x+y)+8/(x-y)=7 is Hyperbola with (h,k)=(29/7 ,3),a= 20/7 ,b= 20/7