What is ((x-1)^2)/9-((y-2)^2)/4 =1 ?

The solution to ((x-1)^2)/9-((y-2)^2)/4 =1 is Hyperbola with (h,k)=(1,2),a=3,b=2

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((x-1)^2)/9-((y-2)^2)/4 =1

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

(h, k) = (1, 2), a = 3, b = 2

Solution steps

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} - \frac{( y - 2 ) ^{2}}{4} = 1

in the form of a standard hyperbola equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (1, 2), a = 3, b = 2

(\frac{( x + 1 )}{16})^{2} - (\frac{( y - 4 )}{25})^{2} = 1

x^{2} - 4 y^{2} - 4 x - 12 = 0

x^{2} - y^{2} + 2 x - 5 y + 10 = 0

- 8 x^{2} + y^{2} - 36 x + 6 y - 27 = 0

x^{2} + 1 - 2 y^{2} = 0

What is ((x-1)^2)/9-((y-2)^2)/4 =1 ?
The solution to ((x-1)^2)/9-((y-2)^2)/4 =1 is Hyperbola with (h,k)=(1,2),a=3,b=2