What is (x^2)/(324/9)-(y^2)/(324/36)=1 ?

The solution to (x^2)/(324/9)-(y^2)/(324/36)=1 is Hyperbola with (h,k)=(0,0),a=6,b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/(324/9)-(y^2)/(324/36)=1

\frac{x ^{2}}{\frac{324}{9}} - \frac{y ^{2}}{\frac{324}{36}} = 1

(h, k) = (0, 0), a = 6, b = 3

Solution steps

\frac{x ^{2}}{\frac{324}{9}} - \frac{y ^{2}}{\frac{324}{36}} = 1

Rewrite

\frac{x ^{2}}{\frac{324}{9}} - \frac{y ^{2}}{\frac{324}{36}} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 6, b = 3

\frac{( x - 5 ) ^{2}}{4 ^{2}} - \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

3 y^{2} - 3 x^{2} + 5 x + 10 y = 5 x^{2} + 1

x^{2} + 8 x - y^{2} - 9 y = 6

\frac{y ^{2}}{16} - \frac{x ^{2}}{49} = 1

(\frac{3 y + 2 x}{18}) (\frac{3 y - 2 x}{2}) = 1

What is (x^2)/(324/9)-(y^2)/(324/36)=1 ?
The solution to (x^2)/(324/9)-(y^2)/(324/36)=1 is Hyperbola with (h,k)=(0,0),a=6,b=3