What is the directrix 3-2x-x^2 ?

The directrix 3-2x-x^2 is y= 17/4

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directrix 3-2x-x^2

directrix

3 - 2 x - x^{2}

y = \frac{17}{4}

Solution steps

Rewrite

y = 3 - 2 x - x^{2}

in the standard form

4 (- \frac{1}{4}) (y - 4) = (x - (- 1))^{2}

(h, k) = (- 1, 4), p = - \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(- 1, 4)

y-coordinate

y = 4 - p

y = 4 - (- \frac{1}{4})

Refine

y = \frac{17}{4}

x^{2} - 16

- 0.0001 x^{2} + 6.4 x + 7600

x^{2} = 6 y

x = 3 y^{2}

y = x^{2} + 4 x - 1