What is the directrix (y+1.5)^2=4(x-2) ?

The directrix (y+1.5)^2=4(x-2) is x=1

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directrix (y+1.5)^2=4(x-2)

directrix

(y + 1.5)^{2} = 4 (x - 2)

x = 1

Solution steps

Rewrite

(y + 1.5)^{2} = 4 (x - 2)

in the standard form:

4 \cdot 1 \cdot (x - 2) = (y - (- 1.5))^{2}

(h, k) = (2, - 1.5), p = 1

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(2, - 1.5)

x-coordinate

x = 2 - p

x = 2 - 1

Refine

x = 1

x = (y - 3)^{2} + 2

14 x^{2}

y = \frac{- 4 x ^{2} + 24 x + 161}{25}

x^{2} - 12 x + 35

x = (2 y + 5)^{2}