What is the axis y=x^2-4x+3 ?

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axis y=x^2-4x+3

axis

y = x^{2} - 4 x + 3

x = 2

Solution steps

y = x^{2} - 4 x + 3

Rewrite

y = x^{2} - 4 x + 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = 3 - x^{2}

y = 2 x^{2} - 3 x 8

y = 2 x^{2} + 3 x - 20

y - 2 = (x - 1)^{2}

y = \frac{x ^{2} x ^{1}}{x}