What is the axis y=2x^2+3x-20 ?

The axis y=2x^2+3x-20 is x=-3/4

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axis y=2x^2+3x-20

axis

y = 2 x^{2} + 3 x - 20

x = - \frac{3}{4}

Solution steps

y = 2 x^{2} + 3 x - 20

Rewrite

y = 2 x^{2} + 3 x - 20

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{169}{8})) = (x - (- \frac{3}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{3}{4}, - \frac{169}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{3}{4}

y - 2 = (x - 1)^{2}

y = \frac{x ^{2} x ^{1}}{x}

y = x^{2} + 3

y = 3 x^{2}

y = 2 x (x - 9) - (x - 9)