What is the axis y=2x^2-3x8 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=2x^2-3x8

axis

y = 2 x^{2} - 3 x 8

x = 6

Solution steps

y = 2 x^{2} - 3 x \cdot 8

Rewrite

y = 2 x^{2} - 3 x \cdot 8

in the standard form

4 \cdot \frac{1}{8} (y - (- 72)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 72), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

y = 2 x^{2} + 3 x - 20

y - 2 = (x - 1)^{2}

y = \frac{x ^{2} x ^{1}}{x}

y = x^{2} + 3

y = 3 x^{2}