What is the axis y=-2x^2-12x-10 ?

The axis y=-2x^2-12x-10 is x=-3

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axis y=-2x^2-12x-10

axis

y = - 2 x^{2} - 12 x - 10

x = - 3

Solution steps

y = - 2 x^{2} - 12 x - 10

Rewrite

y = - 2 x^{2} - 12 x - 10

in the standard form

4 (- \frac{1}{8}) (y - 8) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, 8), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y^{2} = - x

y = - 3 x^{2}

162 x + 731 = - y - 9 x^{2}

y = 2 x^{2} + 10 x + 12

y = \frac{4}{9} x^{2} - 6 x + 5