What is the axis y=-3x^2 ?

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axis y=-3x^2

axis

y = - 3 x^{2}

x = 0

Solution steps

y = - 3 x^{2}

Rewrite

y = - 3 x^{2}

in the standard form:

4 (- \frac{1}{12}) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

162 x + 731 = - y - 9 x^{2}

y = 2 x^{2} + 10 x + 12

y = \frac{4}{9} x^{2} - 6 x + 5

y = 11 - x^{2}

y = (x - 1) (x - 3)