What is the axis y^2=-x ?

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axis y^2=-x

axis

y^{2} = - x

y = 0

Solution steps

y^{2} = - x

Rewrite

y^{2} = - x

in the standard form:

4 (- \frac{1}{4}) (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = - 3 x^{2}

162 x + 731 = - y - 9 x^{2}

y = 2 x^{2} + 10 x + 12

y = \frac{4}{9} x^{2} - 6 x + 5

y = 11 - x^{2}