What is the axis 162x+731=-y-9x^2 ?

The axis 162x+731=-y-9x^2 is x=-9

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axis 162x+731=-y-9x^2

axis

162 x + 731 = - y - 9 x^{2}

x = - 9

Solution steps

162 x + 731 = - y - 9 x^{2}

Rewrite

162 x + 731 = - y - 9 x^{2}

in the standard form

4 (- \frac{1}{36}) (y - (- 2)) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, - 2), p = - \frac{1}{36}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 9

y = 2 x^{2} + 10 x + 12

y = \frac{4}{9} x^{2} - 6 x + 5

y = 11 - x^{2}

y = (x - 1) (x - 3)

x^{2} - 6 x + 8 y - 31 = 0