What is the axis y= 4/9 x^2-6x+5 ?

The axis y= 4/9 x^2-6x+5 is x= 27/4

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axis y= 4/9 x^2-6x+5

axis

y = \frac{4}{9} x^{2} - 6 x + 5

x = \frac{27}{4}

Solution steps

y = \frac{4}{9} x^{2} - 6 x + 5

Rewrite

y = \frac{4}{9} x^{2} - 6 x + 5

in the standard form

4 \cdot \frac{9}{16} (y - (- \frac{61}{4})) = (x - \frac{27}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{27}{4}, - \frac{61}{4}), p = \frac{9}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{27}{4}

y = 11 - x^{2}

y = (x - 1) (x - 3)

x^{2} - 6 x + 8 y - 31 = 0

y = - 4 x^{2} - 8 x - 6

y = - 2 x^{2} - 2 x - 2