What is the axis y=2x^2+10x+12 ?

The axis y=2x^2+10x+12 is x=-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=2x^2+10x+12

axis

y = 2 x^{2} + 10 x + 12

x = - \frac{5}{2}

Solution steps

y = 2 x^{2} + 10 x + 12

Rewrite

y = 2 x^{2} + 10 x + 12

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{1}{2})) = (x - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5}{2}, - \frac{1}{2}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5}{2}

y = \frac{4}{9} x^{2} - 6 x + 5

y = 11 - x^{2}

y = (x - 1) (x - 3)

x^{2} - 6 x + 8 y - 31 = 0

y = - 4 x^{2} - 8 x - 6