What is the axis (x-4)^2=8(y-3) ?

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axis (x-4)^2=8(y-3)

axis

(x - 4)^{2} = 8 (y - 3)

x = 4

Solution steps

(x - 4)^{2} = 8 (y - 3)

Rewrite

(x - 4)^{2} = 8 (y - 3)

in the standard form:

4 \cdot 2 (y - 3) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 3), p = 2

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = - 2 x^{2} + 6 x + 10

y = - 3 (x + 6)^{2} + 4

y^{2} = - 6 x

y \leq 2 x^{2} - 10 x + 10

y = (x + \frac{1}{2}) (x - \frac{1}{3})