What is the axis-x^2+4x-11 ?

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axis-x^2+4x-11

axis

- x^{2} + 4 x - 11

x = 2

Solution steps

y = - x^{2} + 4 x - 11

Rewrite

y = - x^{2} + 4 x - 11

in the standard form

4 (- \frac{1}{4}) (y - (- 7)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 7), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = 5 x^{2} - 9

4 x^{2} - 24 x - 40 y - 4 = 0

x = + (y + 11)^{2} - 14

y = x^{2} - 3 x + 28

y = (x + 1) x