What is the general solution for sin^2(x)-cos(x)-1=0 ?

The general solution for sin^2(x)-cos(x)-1=0 is x=pi+2pin,x= pi/2+2pin,x=(3pi)/2+2pin

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sin^2(x)-cos(x)-1=0

sin^{2} (x) - cos (x) - 1 = 0

x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{2} (x) - cos (x) - 1 = 0

Rewrite using trig identities

- cos (x) - cos^{2} (x) = 0

Solve by substitution

cos (x) = - 1, cos (x) = 0

cos (x) = - 1 : x = π + 2 πn

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

3 tan (2 θ) + 1 = 0

sin^{2} (x) - cos (x) = 0

9 sin (x) = cos (x) - 7

tan (θ) = \frac{1}{- 3}

sin^{2} (θ) - cos^{2} (θ) = sin (θ)

What is the general solution for sin^2(x)-cos(x)-1=0 ?
The general solution for sin^2(x)-cos(x)-1=0 is x=pi+2pin,x= pi/2+2pin,x=(3pi)/2+2pin