What is the general solution for sqrt(3)tan(2θ)+1=0 ?

The general solution for sqrt(3)tan(2θ)+1=0 is θ=(5pi}{12}+\frac{pin)/2

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sqrt(3)tan(2θ)+1=0

3 tan (2 θ) + 1 = 0

θ = \frac{5 π}{12} + \frac{πn}{2}

Solution steps

3 tan (2 θ) + 1 = 0

Move

1

to the right side

3 tan (2 θ) = - 1

Divide both sides by

3

tan (2 θ) = - \frac{3}{3}

General solutions for

tan (2 θ) = - \frac{3}{3}

2 θ = \frac{5 π}{6} + πn

Solve

2 θ = \frac{5 π}{6} + πn : θ = \frac{5 π}{12} + \frac{πn}{2}

θ = \frac{5 π}{12} + \frac{πn}{2}

sin^{2} (x) - cos (x) = 0

9 sin (x) = cos (x) - 7

tan (θ) = \frac{1}{- 3}

sin^{2} (θ) - cos^{2} (θ) = sin (θ)

4 sin (c) + 3 = sin (c) + 1

What is the general solution for sqrt(3)tan(2θ)+1=0 ?
The general solution for sqrt(3)tan(2θ)+1=0 is θ=(5pi}{12}+\frac{pin)/2