What is the general solution for sin(1/x)=0 ?

The general solution for sin(1/x)=0 is x= 1/(2pin),x= 1/(pi(1+2n));\quad n\ne 0,n\ne-1/2

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sin(1/x)=0

sin (\frac{1}{x}) = 0

x = \frac{1}{2 πn}, x = \frac{1}{π ( 1 + 2 n )}; n \neq = 0, n \neq = - \frac{1}{2}

Solution steps

sin (\frac{1}{x}) = 0

General solutions for

sin (\frac{1}{x}) = 0

\frac{1}{x} = 0 + 2 πn, \frac{1}{x} = π + 2 πn

Solve

\frac{1}{x} = 0 + 2 πn : x = \frac{1}{2 πn}; n \neq = 0

Solve

\frac{1}{x} = π + 2 πn : x = \frac{1}{π ( 1 + 2 n )}; n \neq = - \frac{1}{2}

x = \frac{1}{2 πn}, x = \frac{1}{π ( 1 + 2 n )}; n \neq = 0, n \neq = - \frac{1}{2}

cos (θ) = \frac{40}{41}

- 3 cos (2 θ) + 3 = 5 sin (θ)

12 sin^{2} (x) + 18 sin (x) + 6 = 0

csc^{2} (θ) + cot (θ) = 0

sin^{2} (θ) - 2 sin (θ) - 3 = 0

What is the general solution for sin(1/x)=0 ?
The general solution for sin(1/x)=0 is x= 1/(2pin),x= 1/(pi(1+2n));\quad n\ne 0,n\ne-1/2