What is the general solution for sec(θ)= 17/8 ?

The general solution for sec(θ)= 17/8 is θ=1.08083…+2pin,θ=2pi-1.08083…+2pin

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sec(θ)= 17/8

sec (θ) = \frac{17}{8}

θ = 1.08083 \dots + 2 πn, θ = 2 π - 1.08083 \dots + 2 πn

Solution steps

sec (θ) = \frac{17}{8}

Apply trig inverse properties

θ = arcsec (\frac{17}{8}) + 2 πn, θ = 2 π - arcsec (\frac{17}{8}) + 2 πn

Show solutions in decimal form

θ = 1.08083 \dots + 2 πn, θ = 2 π - 1.08083 \dots + 2 πn

3 sin^{2} (x) = 1

3 sin (θ) + 5 = - 2 sin (θ)

2 - 4 sin (θ) = 0

2 cos (t) = 1, - π \leq t \leq π

tan (\frac{x}{3}) = 1, 0 \leq x \leq 2 π

What is the general solution for sec(θ)= 17/8 ?
The general solution for sec(θ)= 17/8 is θ=1.08083…+2pin,θ=2pi-1.08083…+2pin