What is the general solution for -4cos(c)+8=cos(c)+8 ?

The general solution for -4cos(c)+8=cos(c)+8 is c= pi/2+2pin,c=(3pi)/2+2pin

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-4cos(c)+8=cos(c)+8

- 4 cos (c) + 8 = cos (c) + 8

c = \frac{π}{2} + 2 πn, c = \frac{3 π}{2} + 2 πn

Solution steps

- 4 cos (c) + 8 = cos (c) + 8

Solve by substitution

cos (c) = 0

cos (c) = 0 : c = \frac{π}{2} + 2 πn, c = \frac{3 π}{2} + 2 πn

Combine all the solutions

c = \frac{π}{2} + 2 πn, c = \frac{3 π}{2} + 2 πn

sin (x) = - \frac{3 10}{10}

cos (θ) = \frac{1}{58}

cos (4 x + 4) = sin (10 x + 44)

4 tan^{2} (x) - 3 sec^{2} (x) = 0

(sin (t) - 1) cos (t) = 0

What is the general solution for -4cos(c)+8=cos(c)+8 ?
The general solution for -4cos(c)+8=cos(c)+8 is c= pi/2+2pin,c=(3pi)/2+2pin