Is cos^2(x)-cos^2(x)=cot^2(x)cos^2(x) ?

The answer to whether cos^2(x)-cos^2(x)=cot^2(x)cos^2(x) is False

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prove cos^2(x)-cos^2(x)=cot^2(x)cos^2(x)

prove

cos^{2} (x) - cos^{2} (x) = cot^{2} (x) cos^{2} (x)

False

Solution steps

cos^{2} (x) - cos^{2} (x) = cot^{2} (x) cos^{2} (x)

Show that the two sides are not equal

For

cos^{2} (x) - cos^{2} (x) = cot^{2} (x) cos^{2} (x)

plug in

x = 1

cos^{2} (1) - cos^{2} (1) = 0

cos^{2} (1) - cos^{2} (1)

Refine to a decimal form

= 0

cot^{2} (1) cos^{2} (1) = 0.12035 \dots

cot^{2} (1) cos^{2} (1)

Refine to a decimal form

= 0.12035 \dots

The two sides are not equal

\Rightarrow False

2 cos (2 (\frac{π}{4})) = 16 cos (2 (\frac{π}{4}))

- sin (θ) = - sin (- θ)

- 8 cos (2 x) - (0) (2 cos (2 x)) = - 8 cos (2 x)

sec^{2} (x) cot^{2} (x) = 1 + cot^{2} (x)

cos (2 B) = \frac{1 - tan ^{2} ( B )}{1 + tan ^{2} ( B )}

Is cos^2(x)-cos^2(x)=cot^2(x)cos^2(x) ?
The answer to whether cos^2(x)-cos^2(x)=cot^2(x)cos^2(x) is False