What is the general solution for 0=-sqrt(2)sin(x)-1 ?

The general solution for 0=-sqrt(2)sin(x)-1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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0=-sqrt(2)sin(x)-1

0 = - 2 sin (x) - 1

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

0 = - 2 sin (x) - 1

Switch sides

- 2 sin (x) - 1 = 0

Move

1

to the right side

- 2 sin (x) = 1

Divide both sides by

- 2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x, z = sin (2 x + 3 y)

2 sin (3 θ) = 2

2 tan (x) csc (x) + 2 csc (x) + tan (x) = - 1

4 cos (x) + 1 = 2 cos (x)

cos (2 x) + cos (4 x) + cos (6 x) = 0

What is the general solution for 0=-sqrt(2)sin(x)-1 ?
The general solution for 0=-sqrt(2)sin(x)-1 is x=(5pi)/4+2pin,x=(7pi)/4+2pin