What is the general solution for 2cos(x)-1=-1 ?

The general solution for 2cos(x)-1=-1 is x= pi/2+2pin,x=(3pi)/2+2pin

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2cos(x)-1=-1

2 cos (x) - 1 = - 1

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

2 cos (x) - 1 = - 1

Add

1

to both sides

2 cos (x) - 1 + 1 = - 1 + 1

Simplify

2 cos (x) = 0

Divide both sides by

2

cos (x) = 0

General solutions for

cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

- sec (x) = csc (3.45)

cos (2 x) = \frac{8}{17}

tan (x) (csc (x) + 2) = 0

4 cos^{2} (x) = 5 + 4 sin (x), 0 \leq x \leq 2 π

sin (π + θ) = sin (θ)

What is the general solution for 2cos(x)-1=-1 ?
The general solution for 2cos(x)-1=-1 is x= pi/2+2pin,x=(3pi)/2+2pin